1 The basic algorithm

Implement the basic algorithm

After we learned some basic hardware controls in the last chapter, let's make up our basic software lessons.

Enter the year to determine the leap year

A leap year is a noun in the Gregorian calendar. Common year: a year that is divisible by 4 but not by 100 is a common leap year. (2004 is a leap year, 1999 is not); Century years: leap years are those divisible by 400.

The code is as follows :(can be placed in main.py):

def is_leap_year(year):
   if (year % 4) == 0 and (year % 100) != 0 or (year % 400) == 0:
		print("{0} is leap year".format(year))
	else:
		print("{0} not is leap year".format(year))

first in the interpreter using runfile main.py and then run it in the repl

is_leap_year(int(input("input a leap year ")))

• The year 2004 is leap year.
• The year 1999 is not leap year.
• The year 2000 is leap year.
• You can also go ahead and type in more and have it tell you which year is a leap year.

When you type a command in REPL, you are prompted to enter a value, and press ok to confirm the input.